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We are analyzing https://github.com/w3c/csswg-drafts/issues/5784.

Title:
[css-counter-styles] Additive algorithm shouldn't divide by 0 · Issue #5784 · w3c/csswg-drafts
Description:
Not sure if I'm missing something, but consider <style> @counter-style foo { system: additive; additive-symbols: 0 ⚀; } </style> <li value="1" style="list-style: f...
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weight, tabatkins, style, tuple, loirooriol, additive, current, counter, commented, algorithm, symbol, greater, sign, csscounterstyles, closed, foo, additivesymbols, tuples, infinite, added, edits, member, projects, issue, counterstyle, system, styleliststyle, list, fine, append, floor, times, nan, guess, loop, fallback, contributor, author, make, commenter, assert, skip, navigation, pull, requests, actions, security, shouldnt, divide, insideli,

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fallback counter style type projects chromium stop iterating comment metadata assignees valid 'additive-symbols' counter style projects milestone counter symbol removed agenda+ algorithm returns resolution / edits additive-symbols foo inside current tuple current tuple / current tuple additive tuple list-style style purposes counter fallback territory infinite infinite infinite insertions //drafts csswg elements left symbol list algorithm pretty wrong great reason web compat impl difficulties sufficient reason custom symbol properly fall milestone relationships weight multiplied previous step 0-weight entries spec works early-exit final assertion github loop ended make sense assert failed additive weight tuple 0-weight tuple dice

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Should we just skip over 0-weight entries, or call them invalid?
So the algorithm is asking to append ⚀ infinite times?
Value = 1 - 0*∞ = 1 - NaN = NaN, I guess?

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DiscussionForumPosting:
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      headline:[css-counter-styles] Additive algorithm shouldn't divide by 0
      articleBody:Not sure if I'm missing something, but consider ```html <style> @counter-style foo { system: additive; additive-symbols: 0 ⚀; } </style> <li value="1" style="list-style: foo inside"></li> ``` From https://drafts.csswg.org/css-counter-styles/#additive-system > 1. If *value* is initially 0 It's 1, so no-op. > 2. While *value* is greater than 0 and there are elements left in the *symbol list*: Fine, *value* = 1 > 0 and the *symbol list* contains one additive tuple. > 2.1. Pop the first additive tuple from the *symbol list*. This is the *current tuple*. The current tuple is `0 ⚀`. > 2.2. Append the current tuple’s counter symbol to *S* `floor( value / current tuple’s weight )` times (this may be 0). `floor(1 / 0) = floor(∞) = ∞`. So the algorithm is asking to append `⚀` infinite times?? > 2.3 Decrement *value* by the *current tuple*’s *weight* multiplied by the number of times the current tuple was appended to S in the previous step. `value = 1 - 0*∞ = 1 - NaN = NaN`, I guess? > 2. While value is greater than 0 NaN is not greater than 0, presumably. > 3. If the loop ended because value is 0, return S. Otherwise, the given counter value cannot be represented by this counter style, and must instead be represented by the fallback counter style. So I guess it may end up being fine with the fallback counter style. But it just seems pretty wrong for the algorithm to have divisions by 0, infinite insertions, etc. Both [Firefox](https://searchfox.org/mozilla-central/rev/4415bec7a49c50a338167d9c8934527b9cae59d0/layout/style/CounterStyleManager.cpp#164-166) and [Chromium](https://source.chromium.org/chromium/chromium/src/+/master:third_party/blink/renderer/core/css/counter_style.cc;drc=cac8eca73fba35669e706b5c0425f4a2667fb5c8;l=169) stop iterating if the weight is 0 . I think the algorithm should have that check too.
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      url:https://github.com/5784/csswg-drafts/issues/5784
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      headline:[css-counter-styles] Additive algorithm shouldn't divide by 0
      articleBody:Not sure if I'm missing something, but consider ```html <style> @counter-style foo { system: additive; additive-symbols: 0 ⚀; } </style> <li value="1" style="list-style: foo inside"></li> ``` From https://drafts.csswg.org/css-counter-styles/#additive-system > 1. If *value* is initially 0 It's 1, so no-op. > 2. While *value* is greater than 0 and there are elements left in the *symbol list*: Fine, *value* = 1 > 0 and the *symbol list* contains one additive tuple. > 2.1. Pop the first additive tuple from the *symbol list*. This is the *current tuple*. The current tuple is `0 ⚀`. > 2.2. Append the current tuple’s counter symbol to *S* `floor( value / current tuple’s weight )` times (this may be 0). `floor(1 / 0) = floor(∞) = ∞`. So the algorithm is asking to append `⚀` infinite times?? > 2.3 Decrement *value* by the *current tuple*’s *weight* multiplied by the number of times the current tuple was appended to S in the previous step. `value = 1 - 0*∞ = 1 - NaN = NaN`, I guess? > 2. While value is greater than 0 NaN is not greater than 0, presumably. > 3. If the loop ended because value is 0, return S. Otherwise, the given counter value cannot be represented by this counter style, and must instead be represented by the fallback counter style. So I guess it may end up being fine with the fallback counter style. But it just seems pretty wrong for the algorithm to have divisions by 0, infinite insertions, etc. Both [Firefox](https://searchfox.org/mozilla-central/rev/4415bec7a49c50a338167d9c8934527b9cae59d0/layout/style/CounterStyleManager.cpp#164-166) and [Chromium](https://source.chromium.org/chromium/chromium/src/+/master:third_party/blink/renderer/core/css/counter_style.cc;drc=cac8eca73fba35669e706b5c0425f4a2667fb5c8;l=169) stop iterating if the weight is 0 . I think the algorithm should have that check too.
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      url:https://github.com/5784/csswg-drafts/issues/5784
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